Ryosama1Note: Wajib sertai langkah pengerjaan dan No Copy Paste! ​


Ryosama1

Note: Wajib sertai langkah pengerjaan dan No Copy Paste! ​


v = (–4, x, 2)

p.s.o ,
u





v

=

u.v = 2(–4) + 3x + (–1)2

u.v = –8 + 3x – 2

u.v = 3x – 10

|v| = √((–4)²+ x² + 2²)

|v| = √(x² + 20)

p.s.ozon =
u
.
v

|v|

⅓ =




3
x





1
0





√(x²+20)

•••

d


i


k


a


l


i






s


i


l


a


n


g













1( √(x²+20) ) = 3(3x – 10)

√(x²+20) = 9x – 30

(x²+20) = (9x – 30)²

x² + 20 = 81x² – 540x + 900

80x² – 540x + 880 = 0

4x² – 27x + 44 = 0

(4x – 11)(x – 4) = 0

4x = 11

x =




1
1






tidak






bulat

4

x – 4 = 0

x = 4 →

b


i


l


a


tepi langit


g


a


n






b


u


l


a


t

kaprikornus, vektor
v


=


(



4
,

4
,

2


)

nilai dari u + 2v

= (2, 3, –1) + 2( –4, 4, 2 )

= (2–8, 3+8, –1+4)

= (–6, 11, –3) ✔




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