Q.( 3/5 )Dik :p = 12l = 9t = 2Dit :V = ..Lp = ..​

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Q.


( 3/5 )

Dik :

p = 12
l = 9
kaki langit = 2

Dit :

V = ..
Lp = ..​


Volumenya dan luas permukaannya merupakan
\boxed{ \sf \:216~satuan~kubik}
dan
\boxed{ \sf \:300}.

 \:  \:

Pembahasan

Diketahui:

  • Hierarki(p) = 12
  • Lebar(l) = 9
  • Tinggi(lengkung langit) = 2

 \:  \:

Ditanya:

  • Tagihan (V)
  • Luas latar (Lp)

 \:  \:

Dijawab:

 \underline{ \bf| Volume |}

= p × l × t

= 12 × 9 × 2

= 108 × 2

=
\boxed{ \sf \:216~satuan~kubik}

 \:  \:

 \underline{ \bf| Luas~permukaan |}

= 2 × [pl + pt + lt]

= 2 × [ (12 × 9) + (12 × 2) + (9 × 2) ]

= 2 × [108 + 24 + 18]

= 2 × 150

=
\boxed{ \sf \:300}

_____________________


istiscofishofiatumua

Jawaban:

  • diketahui

Panjang = 12

Tumpul pisau = 9

Tinggi = 2

  • ditanya

Debit = .. ?

Luas bidang = .. ?

  • jawab

V
o
l
u
m
e

Debit = p × l × t

Volume = 12 × 9 × 2

Volume = 108 × 2

Volume =
2
1
6


cm³


.


_






_






_






_






_






_






_






_






_






_






_


.

Luas


permukaan

Lp


=


2
(



l


)


+


(



t


)


+


(



t


)

Lp


=


2
(


1
2
×
9


)


+


(


1
2
×
2


)


+


(


9
×
2


)

Lp


=


2
(


1
0
8


+


2
4


+


1
8


)

Lp


=


2
(


1
3
2


+


1
8


)

Lp


=


2
(


1
5
0


)

Lp


=


2


×


1
5
0

Lp


=



3


0


0






cm²


.






_






_






_






_






_






_






_






_






_






_






_


.

  • penali

Hasil
volume
=
2
1
6


cm³

Hasil
luas


permukaan
=
3
0
0


cm²

.